मराठी

Find the sum of all 2-digit natural numbers divisible by 5.

Advertisements
Advertisements

प्रश्न

Find the sum of all 2-digit natural numbers divisible by 5.

बेरीज
Advertisements

उत्तर

The numbers are 10, 15, 20, ..., 95.

Here $$a = 10,\ d = 5, \ l = 95$$. 

Number of terms: $$n = \frac{95 - 10}{5} + 1 = 18$$. 

Sum $$S_{18} = \frac{18}{2}(10 + 95)$$

$$= 9(105)$$

$$= 945$$

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Arithmetic Progression - EXERCISE 10B [पृष्ठ १६७]

APPEARS IN

आर. एस. अग्रवाल Mathematics [English] Class 10 ICSE
पाठ 10 Arithmetic Progression
EXERCISE 10B | Q 9. | पृष्ठ १६७
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×