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Question
Find the product of the following pair of monomial.
− 4p, 7p
Sum
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Solution
The product will be as follows:
− 4p × 7p
= − 4 × p × 7 × p
= (− 4 × 7) × (p × p)
= − 28p2
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Chapter 8: Algebraic Expressions and Identities - EXERCISE 8.2 [Page 97]
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RELATED QUESTIONS
Find the areas of rectangles with the following pairs of monomials as their lengths and breadths, respectively.
(p, q); (10m, 5n); (20x2, 5y2); (4x, 3x2); (3mn, 4np)
Complete the table of products.
|
First monomial→ |
2x |
–5y |
3x2 |
–4xy |
7x2y |
–9x2y2 |
|
Second monomial ↓ |
||||||
| 2x | 4x2 | ... | ... | ... | ... | ... |
| –5y | ... | ... | –15x2y | ... | ... | ... |
| 3x2 | ... | ... | ... | ... | ... | ... |
| – 4xy | ... | ... | ... | ... | ... | ... |
| 7x2y | ... | ... | ... | ... | ... | ... |
| –9x2y2 | ... | ... | ... | ... | ... | ... |
Obtain the product of a, − a2, a3
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\[\left( \frac{2}{5} a^2 b \right) \times \left( - 15 b^2 ac \right) \times \left( - \frac{1}{2} c^2 \right)\]
Multiply: −5cd2 by − 5cd2
Multiply: 12a + 5b by 7a − b
Solve: ( -3x2 ) × ( -4xy)
Solve: (-12x) × 3y2
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