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Question
Find the perimeter and the area of a right angled triangle whose sides are 6 feet, 8 feet and 10 feet
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Solution
Perimeter of a right angled triangle = sum of three sides
= (6 + 8 + 10) feets
= 24 feets
Area of a right angled triangle = `1/2 × ("b" × "h") "unit"^2`
Here the longest side is 10 feet which is the hypoteneous
∴ Sides containing right angle are 6 feet and 8 feet
Let base = 6 feet and height = 8 feet
∴ Area = `1/2 xx 6 xx 8 "feet"^2`
= 24 sq.feet
Area = 24 sq.feet
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