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Question
Find the area of the right-angled triangle with a hypotenuse of 40 cm and one of the other two sides of 24 cm.
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Solution
by applying Pythagoras' theorem,
H2 = P2 + B2
402 = P2 + 242
P2 = 402 - 242
= (40 - 24) (40 + 24)
= 16 × 64 = 1024 cm2
P = `sqrt1024 = 32` cm
A = `1/2 xx "b" xx "h"`
= `1/2 xx 24 xx 32`
= `12 xx 32`
= 384 cm2
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