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Question
Find the area of a right angled triangle whose hypotenuse is 15cm and the base is 9cm.
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Solution
The perpendicular of a right triangle whose hypotenuse is h and base is b, is given by
`sqrt("h"^2 - "b"^2)`
The perpendicular of a right triangle whose hypotenuse is 15 and base is 9, is given by
`sqrt(15^2 - 9^2)`
= `sqrt(225 - 81)`
= `sqrt(144)`
= 12cm
We also know that, Area of a Triangle
= `(1)/(2)"b.h" "i.e." (1)/(2)("Base" xx "Height")`
Area of a Triangle with base
= 9cm and height
= perpendicular
= 12cm
⇒ `(1)/(2)"b.h"`
= `(1)/(2) xx 9 xx 12`
= 54cm2.
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