Question

Find the area of a right angled triangle whose hypotenuse is 15cm and the base is 9cm.

Answer 1

The perpendicular of a right triangle whose hypotenuse is h and base is b, is given by
`sqrt("h"^2 - "b"^2)`
The perpendicular of a right triangle whose hypotenuse is 15 and base is 9, is given by
`sqrt(15^2 - 9^2)`
= `sqrt(225 - 81)`
= `sqrt(144)`
= 12cm

We also know that, Area of a Triangle

= `(1)/(2)"b.h"  "i.e." (1)/(2)("Base" xx "Height")`

Area of a Triangle with base
= 9cm and height
= perpendicular
= 12cm

⇒ `(1)/(2)"b.h"`

= `(1)/(2) xx 9 xx 12`
= 54cm².