Advertisements
Advertisements
प्रश्न
Find the area of the right-angled triangle with a hypotenuse of 40 cm and one of the other two sides of 24 cm.
Advertisements
उत्तर
by applying Pythagoras' theorem,
H2 = P2 + B2
402 = P2 + 242
P2 = 402 - 242
= (40 - 24) (40 + 24)
= 16 × 64 = 1024 cm2
P = `sqrt1024 = 32` cm
A = `1/2 xx "b" xx "h"`
= `1/2 xx 24 xx 32`
= `12 xx 32`
= 384 cm2
APPEARS IN
संबंधित प्रश्न
The length of the sides of a triangle are in the ratio 3: 4: 5. Find the area of the triangle if its perimeter is 144 cm.
The base of a triangular field is three times its height. If the cost of cultivating the field at ₹ 36.72 per 100 m2 is ₹ 49,572; find its base and height.
The given figure shows a right-angled triangle ABC and an equilateral triangle BCD. Find the area of the shaded portion.
Find the area of a triangle, whose sides are :
18 mm, 24 mm and 30 mm
The sides of a triangle are 16 cm, 12 cm, and 20 cm. Find :
(i) area of the triangle ;
(ii) height of the triangle, corresponding to the largest side ;
(iii) height of the triangle, corresponding to the smallest side.
The area of an equilateral triangle is numerically equal to its perimeter. Find its perimeter correct to 2 decimal places.
The cost of fencing a triangular field at the rate of Rs.15 per m is Rs.900. If the lengths of the triangle are in the ratio 3:4:5, find the area of the triangle and the cost of cultivating it at Rs.48 per kg sq.m.
The table given below contains some measures of the triangle. Find the unknown values.
| Side 1 | Side 2 | Side 3 | Perimeter |
| 6 cm | 5 cm | 2 cm | ? |
A piece of wire is 36 cm long. What will be the length of each side if we form an equilateral triangle
Two sides of a triangle are 12 cm and 14 cm. The perimeter of the triangle is 36 cm. What is its third side?
