Advertisements
Advertisements
प्रश्न
Use the information given in the adjoining figure to find :
(i) the length of AC.
(ii) the area of an ∆ABC
(iii) the length of BD, correct to one decimal place.

Advertisements
उत्तर
AB = 24 cm, BC = 7 cm
(i)
AC = `sqrt("AB"^2 + "BC"^2)`
= `sqrt(24^2 + 7^2)`
= `sqrt(576 + 49)`
= `sqrt(625) = 25` cm

(ii)
Area of ΔABC = `1/2 "AB" xx "BC"`
= `1/2 xx 24 xx 7 = 84` cm2
(iii)
BD ⊥ AC
Area ΔABC = `1/2 "AC" xx "BD"`
`84 = 1/2 xx 25 xx "BD"`
⇒ BD = `(84 xx 2)/25 = 168/25 = 6.72` cm
= 6.72 cm ≈ 6.7 cm
APPEARS IN
संबंधित प्रश्न
The length of the sides of a triangle are in the ratio 3: 4: 5. Find the area of the triangle if its perimeter is 144 cm.
Find the area of an isosceles triangle with perimeter is 36 cm and the base is 16 cm.
Two sides of a triangle are 6 cm and 8 cm. If the height of the triangle corresponding to 6 cm side is 4 cm; find :
(i) area of the triangle
(ii) height of the triangle corresponding to 8 cm side.
The sides of a triangle are 16 cm, 12 cm, and 20 cm. Find :
(i) area of the triangle ;
(ii) height of the triangle, corresponding to the largest side ;
(iii) height of the triangle, corresponding to the smallest side.
A field is in the shape of a quadrilateral ABCD in which side AB = 18 m, side AD = 24 m, side BC = 40m, DC = 50 m and angle A = 90°. Find the area of the field.
One of the equal sides of an isosceles triangle is 13 cm and its perimeter is 50 cm. Find the area of the triangle.
The altitude and the base of a triangular field are in the ratio 6: 5. If its cost is ₹ 49,57,200 at the rate of ₹ 36,720 per hectare and 1 hectare = 10,000 sq. m, find (in metre) dimensions of the field.
Find the area of the right-angled triangle with a hypotenuse of 40 cm and one of the other two sides of 24 cm.
Find the perimeter of a triangle with sides measuring 10 cm, 14 cm and 15 cm.
In the following figures, perimeter of ΔABC = perimeter of ΔPQR. Find the area of ΔABC.

