Advertisements
Advertisements
प्रश्न
Find the perimeter and the area of a right angled triangle whose sides are 6 feet, 8 feet and 10 feet
Advertisements
उत्तर
Perimeter of a right angled triangle = sum of three sides
= (6 + 8 + 10) feets
= 24 feets
Area of a right angled triangle = `1/2 × ("b" × "h") "unit"^2`
Here the longest side is 10 feet which is the hypoteneous
∴ Sides containing right angle are 6 feet and 8 feet
Let base = 6 feet and height = 8 feet
∴ Area = `1/2 xx 6 xx 8 "feet"^2`
= 24 sq.feet
Area = 24 sq.feet
APPEARS IN
संबंधित प्रश्न
AD is altitude of an isosceles triangle ABC in which AB = AC = 30 cm and BC = 36 cm. A point O is marked on AD in such a way that ∠BOC = 90o. Find the area of quadrilateral ABOC.
In triangle ABC; angle A = 90o, side AB = x cm, AC = (x + 5) cm and area = 150 cm2. Find the sides of the triangle.
Find the area of an isosceles triangle with perimeter is 36 cm and the base is 16 cm.
The perimeter of a triangle is 450 m and its side are in the ratio 12: 5: 13. Find the area of the triangle.
Two sides of a triangle are 6 cm and 8 cm. If the height of the triangle corresponding to 6 cm side is 4 cm; find :
(i) area of the triangle
(ii) height of the triangle corresponding to 8 cm side.
Two sides of a triangle are 6.4 m and 4.8 m. If the height of the triangle corresponding to 4.8 m side is 6 m;
find :
(i) area of the triangle ;
(ii) height of the triangle corresponding to 6.4 m sides.
Find the area of the right-angled triangle with a hypotenuse of 40 cm and one of the other two sides of 24 cm.
The cost of fencing a triangular field at the rate of Rs.15 per m is Rs.900. If the lengths of the triangle are in the ratio 3:4:5, find the area of the triangle and the cost of cultivating it at Rs.48 per kg sq.m.
The table given below contains some measures of the triangle. Find the unknown values.
| Side 1 | Side 2 | Side 3 | Perimeter |
| 11 feet | ? | 9 feet | 28 feet |
Two sides of a triangle are 12 cm and 14 cm. The perimeter of the triangle is 36 cm. What is its third side?
