English
Tamil Nadu Board of Secondary EducationHSC Science Class 11

Find the equation of the lines passing through the point (1,1) and (– 2, 3)

Advertisements
Advertisements

Question

Find the equation of the lines passing through the point (1,1) and (– 2, 3)

Sum
Advertisements

Solution

The equation of line joining the two points (x1, y1) and (x2, y2) is

`(y - y_1)/(y_2 - y_1) = (x - 1)/(– 2 – 1)`

Given (x1, y1) = (1, 1), (x2, y2) = (– 2, 3)

∴ The equation of the required line is

`(y - 1)/(3 - 1) = (x - 1)/(- 2 - 1)`

`(y - 1)/2 = (x - 1)/( - 3)`

– 3(y – 1) = 2(x – 1)

– 3y + 3 = 2x – 2

2x + 3y – 2 – 3 = 0

2x + 3y – 5 = 0

shaalaa.com
  Is there an error in this question or solution?
Chapter 6: Two Dimensional Analytical Geometry - Exercise 6.2 [Page 260]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 6 Two Dimensional Analytical Geometry
Exercise 6.2 | Q 1. (iii) | Page 260
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×