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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा ११

Find the equation of the lines passing through the point (1,1) and (– 2, 3)

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प्रश्न

Find the equation of the lines passing through the point (1,1) and (– 2, 3)

योग
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उत्तर

The equation of line joining the two points (x1, y1) and (x2, y2) is

`(y - y_1)/(y_2 - y_1) = (x - 1)/(– 2 – 1)`

Given (x1, y1) = (1, 1), (x2, y2) = (– 2, 3)

∴ The equation of the required line is

`(y - 1)/(3 - 1) = (x - 1)/(- 2 - 1)`

`(y - 1)/2 = (x - 1)/( - 3)`

– 3(y – 1) = 2(x – 1)

– 3y + 3 = 2x – 2

2x + 3y – 2 – 3 = 0

2x + 3y – 5 = 0

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Two Dimensional Analytical Geometry - Exercise 6.2 [पृष्ठ २६०]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 6 Two Dimensional Analytical Geometry
Exercise 6.2 | Q 1. (iii) | पृष्ठ २६०
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