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प्रश्न
Find the equation of the lines passing through the point (1,1) and (– 2, 3)
बेरीज
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उत्तर
The equation of line joining the two points (x1, y1) and (x2, y2) is
`(y - y_1)/(y_2 - y_1) = (x - 1)/(– 2 – 1)`
Given (x1, y1) = (1, 1), (x2, y2) = (– 2, 3)
∴ The equation of the required line is
`(y - 1)/(3 - 1) = (x - 1)/(- 2 - 1)`
`(y - 1)/2 = (x - 1)/( - 3)`
– 3(y – 1) = 2(x – 1)
– 3y + 3 = 2x – 2
2x + 3y – 2 – 3 = 0
2x + 3y – 5 = 0
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पाठ 6: Two Dimensional Analytical Geometry - Exercise 6.2 [पृष्ठ २६०]
