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Question
Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):
(ax + b) (cx + d)2
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Solution
Let f(x) = (ax + b)(cx + d)2
By Leibnitz product rule,
∴ `f'(x) = (ax + b) d/dx (cx + d)^2 + (cx + d)^2 d/dx (ax + d)`
= `(ax + b) d/dx (c^2 x^2 + 2cdx + d^2) + (cx + d)^2 d/dx (ax + b)`
= `(ax + b)[d/dx (c^2x^2) + d/dx (2cdx) + d/dx d^2] + (cx + d)^2 [d/dx ax + d/dx b]`
= (ax + b)(2c2x + 2cd) + (cx + d2)a
= 2c(ax + b) (cx + d) + a(cx + d)2
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