English

log ( 1 √ x ) + 5 x a − 3 a x + 3 √ x 2 + 6 4 √ x − 3 - Mathematics

Advertisements
Advertisements

Question

\[\log\left( \frac{1}{\sqrt{x}} \right) + 5 x^a - 3 a^x + \sqrt[3]{x^2} + 6 \sqrt[4]{x^{- 3}}\] 

Advertisements

Solution

\[\frac{d}{dx}\left( \log \left( \frac{1}{\sqrt{x}} \right) + 5 x^a - 3 a^x + \sqrt[3]{x^2} + 6 \sqrt[4]{x^{- 3}} \right)\]
\[ = \frac{d}{dx}\left[ log \left( x^\frac{- 1}{2} \right) \right] + 5\frac{d}{dx}\left( x^a \right) - 3\frac{d}{dx}\left( a^x \right) + \frac{d}{dx}\left( x^\frac{2}{3} \right) + 6\frac{d}{dx}\left( x^\frac{- 3}{4} \right)\]
\[ = \frac{d}{dx}\left( \frac{- 1}{2}\log x \right) + 5\frac{d}{dx}\left( x^a \right) - 3\frac{d}{dx}\left( a^x \right) + \frac{d}{dx}\left( x^\frac{2}{3} \right) + 6\frac{d}{dx}\left( x^\frac{- 3}{4} \right)\]
\[ = \frac{- 1}{2} . \frac{1}{x} + 5a x^{a - 1} - 3 a^x \log a + \frac{2}{3} x^\frac{- 1}{3} + 6\left( \frac{- 3}{4} \right) x^\frac{- 7}{4} \]
\[ = \frac{- 1}{2x} + 5a x^{a - 1} - 3 a^x \log a + \frac{2}{3} x^\frac{- 1}{3} - \frac{9}{2} x^\frac{- 7}{4} \]
\[\]

 

shaalaa.com
  Is there an error in this question or solution?
Chapter 30: Derivatives - Exercise 30.3 [Page 34]

APPEARS IN

RD Sharma Mathematics [English] Class 11
Chapter 30 Derivatives
Exercise 30.3 | Q 16 | Page 34

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find the derivative of `2/(x + 1) - x^2/(3x -1)`.


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

`(ax + b)/(px^2 + qx + r)`


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

`4sqrtx - 2`


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

(ax + b)n (cx + d)m


Find the derivative of f (x) = 99x at x = 100 


\[\frac{x^2 + 1}{x}\]


\[\frac{x + 1}{x + 2}\]


\[\frac{1}{\sqrt{3 - x}}\]


 x2 + x + 3


Differentiate  of the following from first principle: 

− x


Differentiate  of the following from first principle:

sin (x + 1)


Differentiate  of the following from first principle:

sin (2x − 3)


Differentiate each of the following from first principle:

 x2 sin x


Differentiate each of the following from first principle:

\[e^\sqrt{ax + b}\]


Differentiate each of the following from first principle:

\[a^\sqrt{x}\]


tan (2x + 1) 


2 sec x + 3 cot x − 4 tan x


\[\text{ If } y = \left( \sin\frac{x}{2} + \cos\frac{x}{2} \right)^2 , \text{ find } \frac{dy}{dx} at x = \frac{\pi}{6} .\]


x5 ex + x6 log 


(x sin x + cos x ) (ex + x2 log x


x4 (5 sin x − 3 cos x)


x−3 (5 + 3x


Differentiate in two ways, using product rule and otherwise, the function (1 + 2 tan x) (5 + 4 cos x). Verify that the answers are the same. 


\[\frac{e^x - \tan x}{\cot x - x^n}\] 


\[\frac{1 + 3^x}{1 - 3^x}\]


\[\frac{p x^2 + qx + r}{ax + b}\]


\[\frac{x}{\sin^n x}\]


\[\frac{1}{a x^2 + bx + c}\] 


If x < 2, then write the value of \[\frac{d}{dx}(\sqrt{x^2 - 4x + 4)}\] 


Write the value of the derivative of f (x) = |x − 1| + |x − 3| at x = 2.


If f (x) = |x| + |x−1|, write the value of \[\frac{d}{dx}\left( f (x) \right)\]


If f (1) = 1, f' (1) = 2, then write the value of \[\lim_{x \to 1} \frac{\sqrt{f (x)} - 1}{\sqrt{x} - 1}\] 


If f (x) =  \[\log_{x_2}\]write the value of f' (x). 


Mark the correct alternative in of the following:

If \[y = \sqrt{x} + \frac{1}{\sqrt{x}}\] then \[\frac{dy}{dx}\] at x = 1 is


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×