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Question
Find the change in length of a second’s pendulum, if the acceleration due to gravity at the place changes from 9.75 m/s2 to 9.8 m/s2.
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Solution
Data: gf =9.75 m/s2 , g2 = 9.8 m/s2
Length of a seconds pendulum, L = `"g"/π^2`
∴ L1 = `"g"_1/"π"^2=9.75/9.872` = 0.9876 m
and L2 = `"g"_2/π^2=9.8/9.872` = 0.9927 m
Find the change in length
ΔL = L2 − L1
= 0.9927 − 0.9876
= 0.0051 m = 5.1 mm
∴ The length of the second's pendulum must be increased from 0.9876 m to 0.9927 m, i.e., by 0.0051 m.
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