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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Find the change in length of a second’s pendulum, if the acceleration due to gravity at the place changes from 9.75 m/s2 to 9.8 m/s2.

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प्रश्न

Find the change in length of a second’s pendulum, if the acceleration due to gravity at the place changes from 9.75 m/s2 to 9.8 m/s2.

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उत्तर

Data: gf =9.75 m/s2 , g2 = 9.8 m/s2

Length of a seconds pendulum, L = `"g"/π^2`

∴ L1 = `"g"_1/"π"^2=9.75/9.872` = 0.9876 m

and L2 = `"g"_2/π^2=9.8/9.872` = 0.9927 m

Find the change in length

ΔL = L2 − L1

= 0.9927 − 0.9876

= 0.0051 m = 5.1 mm

∴ The length of the second's pendulum must be increased from 0.9876 m to 0.9927 m, i.e., by 0.0051 m.

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पाठ 5: Oscillations - Exercises [पृष्ठ १३०]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
पाठ 5 Oscillations
Exercises | Q 15 | पृष्ठ १३०

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