Advertisements
Advertisements
Question
Find the area of a rectangle whose length and breadth are 25 m and 16 cm.
Advertisements
Solution
Length of rectangle = 25 cm
Breadth of rectangle = 16 cm
Area of rectangle = l × b or AB × BC
= 25 × 16 cm2 = 400 cm2
∴ Area of rectangle = 400 cm2
APPEARS IN
RELATED QUESTIONS
If AD is a median of a triangle ABC, then prove that triangles ADB and ADC are equal in
area. If G is the mid-point of median AD, prove that ar (Δ BGC) = 2 ar (Δ AGC).
PQRS is a trapezium having PS and QR as parallel sides. A is any point on PQ and B is a point on SR such that AB || QR. If area of ΔPBQ is 17cm2, find the area of ΔASR.
A, B, C, D are mid-points of sides of parallelogram PQRS. If ar (PQRS) = 36 cm2, then ar (ABCD) =
Diagonal AC and BD of trapezium ABCD, in which AB || DC, intersect each other at O. The triangle which is equal in area of ΔAOD is
What will happen to the area of a rectangle, if its length and breadth both are trebled?
Length of a rectangle is 30 m and its breadth is 20 m. Find the increase in its area if its length is increased by 10 m and its breadth is doubled.
So the area of piece A = ________ square cm
Karunya bought three fields.
Find the area of all three fields.
- Field (A) ____________ square metre.
- Field (B) ____________ square metre.
- Field (C) ____________ square metre.
Measure the length of the floor of your classroom in meters. Also measure the width.
- If you want to move around easily then how many children do you think should be there in one square meter?
Is the area of both your footprints the same?
