Advertisements
Advertisements
Question
Find the smallest number that must be subtracted from each of the numbers 20, 29, 84 and 129 so that they are in proportion.
Advertisements
Solution
Let x be subtracted from each number so that 20-x, 29-x, 84-x and 129-x are in proportion.
`therefore (20 - "x")/(29 - "x") = (84 - "x")/(129 - "x")`
⇒ (20 - x)(129 - x) = (29 - x)(84 - x)
⇒ 2580- 129x - 20x + x2 = 2436 - 84x - 29x + x2
⇒ 2580 - 149x = 2436 - 113x
⇒ 36x = 144
⇒ x = 4
Hence, 4 is to be subtracted from 20, 29, 84 and 129 for them to be in proportion.
APPEARS IN
RELATED QUESTIONS
If x2, 4 and 9 are in continued proportion, find x.
What least number must be subtracted from each of the numbers 7, 17 and 47 so that the remainders are in continued proportion?
Find the third proportion to the following :
3 and 15
If u, v, w, and x are in continued proportion, then prove that (2u+3x) : (3u+4x) : : (2u3+3v3) : (3u3+4v3)
`("pqr")^2 (1/"p"^4 + 1/"q"^4 + 1/"r"^4) = ("p"^4 + "q"^4 + "r"^4)/"q"^2`
Find the third proportional to:
x - y, x2 - y2
If 2x – 1, 5x – 6, 6x + 2 and 15x – 9 are in proportion, find the value of x.
`square` : 24 : : 3 : 8
Sleeping time of a python in a 24 hour clock is represented by the shaded portion in the following figure.
The ratio of sleeping time to awaking time is ______.
Determine if the following ratios form a proportion. Also, write the middle terms and extreme terms where the ratios form a proportion.
200 mL : 2.5 litre and ₹ 4 : ₹ 50
Unequal masses will not balance on a fulcrum if they are at equal distance from it; one side will go up and the other side will go down.
Unequal masses will balance when the following proportion is true:
`("mass"1)/("length"2) = ("mass"2)/("length"1)`
Two children can be balanced on a seesaw when
`("mass"1)/("length"2) = ("mass"2)/("length"1)`. The child on the left and child on the right are balanced. What is the mass of the child on the right?
