Advertisements
Advertisements
Question
Find the smallest number that must be subtracted from each of the numbers 20, 29, 84 and 129 so that they are in proportion.
Advertisements
Solution
Let x be subtracted from each number so that 20-x, 29-x, 84-x and 129-x are in proportion.
`therefore (20 - "x")/(29 - "x") = (84 - "x")/(129 - "x")`
⇒ (20 - x)(129 - x) = (29 - x)(84 - x)
⇒ 2580- 129x - 20x + x2 = 2436 - 84x - 29x + x2
⇒ 2580 - 149x = 2436 - 113x
⇒ 36x = 144
⇒ x = 4
Hence, 4 is to be subtracted from 20, 29, 84 and 129 for them to be in proportion.
APPEARS IN
RELATED QUESTIONS
If a/b = c/d prove that each of the given ratio is equal to `sqrt((3a^2 - 10c^2)/(3b^2 - 10d^2))`
If a, b and c are in continued proportion, prove that `(a^2 + ab + b^2)/(b^2 + bc + c^2) = a/c`
If `(4m + 3n)/(4m - 3n) = 7/4`, use properties of proportion to find `(2m^2 - 11n^2)/(2m^2 + 11n^2)`
Write (T) for true and (F) for false in case of the following:
32 kg : Rs 36 : : 8 kg : Rs 9
The 1st, 3rd, and 4th terms of a proportion are 12, 8, and 14 respectively. Find the 2nd term.
The ratio 92 : 115 in its simplest for is
If 25 : 35 : : 45 : x, then the value of x is
In a fort, 550 men had provisions for 28 days. How many days will it last for 700 men?
If a, b, c are in continued proportion, prove that: `(1)/a^3 + (1)/b^3 + (1)/c^3 = a/(b^2c^2) + b/(c^2a^2) + c/(a^2b^2)`
Choose the correct answer from the given options :
The fourth proportional to 3, 4, 5 is
