Advertisements
Advertisements
प्रश्न
Find the smallest number that must be subtracted from each of the numbers 20, 29, 84 and 129 so that they are in proportion.
Advertisements
उत्तर
Let x be subtracted from each number so that 20-x, 29-x, 84-x and 129-x are in proportion.
`therefore (20 - "x")/(29 - "x") = (84 - "x")/(129 - "x")`
⇒ (20 - x)(129 - x) = (29 - x)(84 - x)
⇒ 2580- 129x - 20x + x2 = 2436 - 84x - 29x + x2
⇒ 2580 - 149x = 2436 - 113x
⇒ 36x = 144
⇒ x = 4
Hence, 4 is to be subtracted from 20, 29, 84 and 129 for them to be in proportion.
APPEARS IN
संबंधित प्रश्न
Check whether the following numbers are in continued proportion.
1, 2, 3
a, b, c are in continued proportion. If a = 3 and c = 27 then find b.
Find the fourth proportion to the following :
(x2 - y2),(x3 + y3)anc(x3 - xy2 + x2y- y3)
Find the third proportion to the following :
`9/25` and `18/25`
If 2x – 1, 5x – 6, 6x + 2 and 15x – 9 are in proportion, find the value of x.
Determine if the following numbers are in proportion:
32, 48, 70, 210
The angles of a triangle are in the ratio 3 : 1 : 2. The measure of the largest angle is
If ax = by = cz; prove that `x^2/"yz" + y^2/"zx" + z^2/"xy" = "bc"/a^2 + "ca"/b^2 + "ab"/c^2`
If a, b, c, d, e are in continued proportion, prove that: a : e = a4 : b4.
Determine if the following are in proportion.
33, 44, 75, 100
