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If a, b and c are in continued proportion, prove that a2+ab+b2b2+bc+c2=ac - Mathematics

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प्रश्न

If a, b and c are in continued proportion, prove that `(a^2 + ab + b^2)/(b^2 + bc + c^2) = a/c`

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उत्तर

Given, a, b and c are in continued proportion.

Therefore,

`a/b = b/c`

ac = b2

Here,

`(a^2 + ab + b^2)/(b^2 + bc + c^2) = (a^2 + ab + ac)/(ac + bc + c^2)`

= `(a(a + b + c))/(c(a + b + c))`

= `a/c`

Hence proved.

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