Advertisements
Advertisements
Question
Find the lateral surface area and total surface area of a cuboid of length 80 cm, breadth 40 cm and height 20 cm.
Advertisements
Solution
It is given that
Cuboid length= 80cm= L
Breath = 40cm=b
Height=20cm=h
WKT,
Total surface area = `2[lb+bh+hl]`
`=2[(80)(40)+40(20)+20(80)]`
`=2[3200+800+1600]`
`=2[5600]`
`=11,200cm^2`
`"Lateral surface area" = 2[l+b]h=2[80+40]20`
`=40(120)`
`=4800cm^2`
APPEARS IN
RELATED QUESTIONS
A cubical box has each edge 10 cm and another cuboidal box is 12.5 cm long, 10 cm wide and 8 cm high.
(i) Which box has the greater lateral surface area and by how much?
(ii) Which box has the smaller total surface area and by how much?
Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth, and height of 15 m, 10 m, and 7 m, respectively. From each can of paint, 100 m2 of area is painted. How many cans of paint will she need to paint the room?
Length, breadth and height of a cuboid shape box of medicine is 20 cm, 12 cm and 10 cm respectively. Find the surface area of vertical faces and total surface area of this box.
The volume of a cuboid is 3456 cm3. If its length = 24 cm and breadth = 18 cm ; find its height.
Find the capacity of a cylindrical container with an internal diameter of 28 cm and a height of 20 cm.
A cuboid is 8 m long, 12 m broad and 3.5 high, Find its
(i) total surface area
(ii) lateral surface area
The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of ₹ 10 per m2 is ₹ 15,000, find the height of the hall.
In a building, there are 24 cylindrical pillars. For each pillar, the radius is 28 m, and the height is 4 m. Find the total cost of painting the curved surface area of the pillars at the rate of ₹ 8 per m2.
Find the Total Surface Area and the Lateral Surface Area of a cuboid whose dimensions are: length = 20 cm, breadth = 15 cm, height = 8 cm
Find the length of the largest pole that can be placed in a room of dimensions 12 m × 4 m × 3 m.
