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The length, breadth and height of a rectangular solid are in the ratio 5 : 4 : 2. If the total surface area is 1216 cm^2, find the length, the breadth and the height of the solid.

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Question

The length, breadth and height of a rectangular solid are in the ratio 5 : 4 : 2. If the total surface area is 1216 cm2, find the length, the breadth and the height of the solid.

Sum
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Solution

The rectangular solid is a cuboid.

Let the length of the cuboid = 5a, breadth = 4a and height = 2a

Total surface area of a cuboid of length l, breadth b and height h = 2(l × b + b × h + l × h)

Given,

Total surface area of the cuboid = 1216 cm2

⇒ 2(5a × 4a + 4a × 2a + 2a × 5a) = 1216 cm2

⇒ 76a2 = 1216

⇒ a = 4.

Hence, the length of the cuboid = 5a = 20 cm, breadth = 4a = 16 cm, height = 2a = 8 cm.

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Chapter 21: Solids [Surface Area and Volume of 3-D Solids] - Exercise 21 (A) [Page 269]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 21 Solids [Surface Area and Volume of 3-D Solids]
Exercise 21 (A) | Q 1 | Page 269
Nootan Mathematics [English] Class 9 ICSE
Chapter 16 Mensuration
Exercise 16D | Q 9. | Page 344

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