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Find the Equation of Two Straight Lines Which Are Parallel to X + 7y + 2 = 0 and at Unit Distance from the Point (1, −1). Answer 3:

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Question

Find the equation of two straight lines which are parallel to + 7y + 2 = 0 and at unit distance from the point (1, −1).

Answer 3:

Short/Brief Note
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Solution

The equation of given line is  + 7y + 2 = 0        ... (1)
The equation of a line parallel to line + 7y + 2 = 0 is given below: 
\[x + 7y + \lambda = 0\]             ... (2)

The line  \[x + 7y + \lambda = 0\]  is at a unit distance from the point (1, −1).

\[\therefore 1 = \left| \frac{1 - 7 + \lambda}{\sqrt{1 + 49}} \right|\]
\[ \Rightarrow \lambda - 6 = \pm 5\sqrt{2}\]
\[ \Rightarrow \lambda = 6 + 5\sqrt{2}, 6 - 5\sqrt{2}\]

Required lines :

\[x + 7y + 6 + 5\sqrt{2} = 0 \] \[\text{ and }x + 7y + 6 - 5\sqrt{2} = 0\]

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Chapter 23: The straight lines - Exercise 23.16 [Page 114]

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R.D. Sharma Mathematics [English] Class 11
Chapter 23 The straight lines
Exercise 23.16 | Q 3 | Page 114

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