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Question
Find `"dy"/"dx" if, sqrt"x" + sqrt"y" = sqrt"a"`
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Solution
`sqrt"x" + sqrt"y" = sqrt"a"`
Differentiating both sides w.r.t. x, we get
`1/(2 sqrt"x") + 1/(2sqrt"y") * "dy"/"dx" = 0`
∴ `1/(2sqrt"y") * "dy"/"dx" = (-1)/(2sqrt"x")`
∴ `"dy"/"dx" = - sqrt("y"/"x")`
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