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Find D Y D X Y = ( Tan X ) Log X + Cos 2 ( π 4 ) ? - Mathematics

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Question

Find \[\frac{dy}{dx}\] \[y = \left( \tan x \right)^{\log x} + \cos^2 \left( \frac{\pi}{4} \right)\] ?

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Solution

\[\text{ We have, y }= \left( \tan x \right)^{\log x }+ \cos^2 \left( \frac{\pi}{4} \right)\]

\[ \Rightarrow y = e^{ \log \left( \tan x \right)^{\log x }} + \cos^2 \left( \frac{\pi}{4} \right)\]

\[ \Rightarrow y = e^{ \log x \log \tan x }+ \cos^2 \left( \frac{\pi}{4} \right)\]

Differentiating with respect to x using chain rule,

\[\frac{dy}{dx} = \frac{d}{dx}\left( e^{\log x \log \tan x} \right) + \frac{d}{dx} \cos^2 \left( \frac{\pi}{4} \right)\]

\[ = e^{\log x \log \tan x } \frac{d}{dx}\left( \log x \log \tan x \right) + 0\]

\[ = e^{\log \left( \tan x \right)^{\log x}} \left[ \log x\frac{d}{dx}\left( \log \tan x \right) + \log \tan x\frac{d}{dx}\left( \log x \right) \right] \]

\[ = \left( \tan x \right)^{\log x } \left[ \log x\left( \frac{1}{\tan x} \right)\frac{d}{dx}\left( \tan x \right) + \log \tan x\left( \frac{1}{x} \right) \right]\]

\[ = \left( \tan x \right)^{\log x} \left[ \log x\left( \frac{1}{\tan x} \right)\left( \sec^2 x \right) + \frac{\log \tan x}{x} \right]\]

\[ = \left( \tan x \right)^{\log x } \left[ \log x\left( \frac{\sec^2 x}{\tan x} \right) + \frac{\log \tan x}{x} \right]\]

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Chapter 11: Differentiation - Exercise 11.05 [Page 89]

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RD Sharma Mathematics [English] Class 12
Chapter 11 Differentiation
Exercise 11.05 | Q 30 | Page 89

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