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Question
Find `(d^2y)/(dx^2)` , if y = log x
Sum
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Solution
∵ y = log x
∵ `(dy)/(dx) = 1/x = x^-1`
and `(d^2y)/(dx^2) = -x^-2 = (-1)/x^2`
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Find `(d^2y)/(dx^2)` , if y = log x
∵ y = log x
∵ `(dy)/(dx) = 1/x = x^-1`
and `(d^2y)/(dx^2) = -x^-2 = (-1)/x^2`