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Find an anti derivative (or integral) of the following function by the method of inspection. (axe + b)2

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Question

Find an anti derivative (or integral) of the following function by the method of inspection.

(axe + b)2

Sum
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Solution

We know that,

`d/dx` (ax + b)2 = 3a (ax + b)2

`=> (ax + b)^2 = 1/(3a) d/dx (ax + b)^3`

or (ax + b)2 = `d/dx[1/(3a) (axee + b)^3]` 

Hence, the antiderivative of (ax + b)2 is `1/(3a)`(ax + b)3.

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Chapter 7: Integrals - Exercise 7.1 [Page 299]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 7 Integrals
Exercise 7.1 | Q 4 | Page 299

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