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प्रश्न
Find an anti derivative (or integral) of the following function by the method of inspection.
(axe + b)2
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उत्तर
We know that,
`d/dx` (ax + b)2 = 3a (ax + b)2
`=> (ax + b)^2 = 1/(3a) d/dx (ax + b)^3`
or (ax + b)2 = `d/dx[1/(3a) (axee + b)^3]`
Hence, the antiderivative of (ax + b)2 is `1/(3a)`(ax + b)3.
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