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Karnataka Board PUCPUC Science Class 11

Figure Shows a Source of Sound Moving Along X-axis at a Speed of 22 M S−1continuously Emitting a Sound of Frequency 2.0 Khz Which Travels in Air at a Speed of 330 M S−1.

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Question

Figure shows a source of sound moving along X-axis at a speed of 22 m s−1continuously emitting a sound of frequency 2.0 kHz which travels in air at a speed of 330 m s−1. A listener Q stands on the Y-axis at a distance of 330 m from the origin. At t = 0, the sources crosses the origin P. (a) When does the sound emitted from the source at P reach the listener Q? (b) What will be the frequency heard by the listener at this instant? (c) Where will the source be at this instant?

Sum
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Solution

Given:
Velocity of sound in air v = 330 ms−1
Distance travelled by the sound s = 330 m
Frequency of the sound n = 2 kHz
(a) Velocity v = \[\frac{s}{t}\] 

 ∴  Time t = \[\frac{330}{330}   =   1  s\]

(b) The frequency of sound heard by the listener is 2 kHz.
 (Since frequency does not depend on distance.)
(c)  
s = 22 m (= 22 m/s \[\times\]1 s) away from P on x-axis. 

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Chapter 16: Sound Waves - Exercise [Page 357]

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HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 16 Sound Waves
Exercise | Q 85 | Page 357

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