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An Operator Sitting in His Base Camp Sends a Sound Signal of Frequency 400 Hz. the Signal is Reflected Back from a Car Moving Towards Him. - Physics

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Question

An operator sitting in his base camp sends a sound signal of frequency 400 Hz. The signal is reflected back from a car moving towards him. The frequency of the reflected sound is found to be 410 Hz. Find the speed of the car. Speed of sound in air = 324 m s−1

Sum
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Solution

Given:
 Velocity of sound in air v = 324 ms−1
 Frequency of sound sent by source \[n_0\]= 400 Hz
 Let the speed of the car be x m/s.
 The frequency of sound heard at the car is given by :

\[n = \frac{v + v_{car}}{v} \times  n_0 \] 

\[ \Rightarrow   n = \frac{324 + x}{324} \times 400       .  .  .  .  . \left( 1 \right)\]

 If  \[n_1\] is the frequency of sound heard by the operator, then its value is given by :

\[n_1  = \frac{324}{324 - x} \times n\]

\[410 = \frac{324}{324 - x} \times n\]

 On substituting the value of from equation (1), we have :

\[410 = \frac{324}{\left( 324 - x \right)} \times \frac{\left( 324 + x \right)}{324} \times 400\] 

\[ \Rightarrow   410 = \left( \frac{324 + x}{324 - x} \right) \times 400\] 

\[ \Rightarrow   410  \left( 324 - x \right) = 400\left( 324 + x \right)\] 

\[ \Rightarrow   324  \left( 410 - 400 \right) = 810x\] 

\[ \Rightarrow   x = 4 \text{ m/s }\]

 The speed of the car is 4 m/s.

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Speed of Wave Motion
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Chapter 16: Sound Waves - Exercise [Page 357]

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HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 16 Sound Waves
Exercise | Q 84 | Page 357

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