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Question
Factorize the following expressions
1- 27a3
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Solution
= (1)3 - (3a)3
= (1- 3a)(12 +1´ 3a + (3a)2 ) [∵ a3 - b3 = (a - b)(a2 + ab + b2 )]
= (1- 3a)(1+ 3a + 9a2)
∴ 1- 27a3 = (1- 3a)(1+ 3a + 9a2)
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