Advertisements
Advertisements
Question
Factorize the following expressions
1- 27a3
Advertisements
Solution
= (1)3 - (3a)3
= (1- 3a)(12 +1´ 3a + (3a)2 ) [∵ a3 - b3 = (a - b)(a2 + ab + b2 )]
= (1- 3a)(1+ 3a + 9a2)
∴ 1- 27a3 = (1- 3a)(1+ 3a + 9a2)
APPEARS IN
RELATED QUESTIONS
Get the algebraic expression in the following case using variables, constants and arithmetic operations.
Number 5 added to three times the product of numbers m and n.
Factorize `2x^2 - 5/6x + 1/12`
Factorize `21x^2 - 2x + 1/21`
Factorize the following expressions:
p3 + 27
a3 + 8b3 + 64c3 - 24abc
Separate the constants and variables from the following :
`-7,7+"x",7"x"+"yz",sqrt5,sqrt("xy"),(3"yz")/8,4.5"y"-3"x",`
8 −5, 8 − 5x, 8x −5y × p and 3y2z ÷ 4x
Evaluate: (4m - 2)(m2 + 5m - 6)
Divide:
n2 − 2n + 1 by n − 1
Divide: m2 − 2mn + n2 by m − n
In the formula, area of circle = πr2, the numerical constant of the expression πr2 is ______.
