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Question
Factorise the following expression.
`1/2y^2-8z^2`
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Solution
`1/2y^2 - 8z^2`
= `1/2(y^2 - 16z^2)`
a2 − b2 = (a + b) (a − b)
a = y2
b = 42 = 16
∴ = `1/2[(y)^2 - (4z)^2]`
`1/2(y^2 - 16z^2) = 1/2(y + 4z)(y - 4z)`
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Factorise the following expression.
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Match the following :
| Column A | Column B |
| (a) `x/2` = 10 | (i) x = 4 |
| (b) 20 = 6x − 4 | (ii) x = 1 |
| (c) 2x − 5 = 3 − x | (iii) x = 20 |
| (d) 7x − 4 − 8x = 20 | (iv) x = `8/3` |
| (e) `4/11 - x = (-7)/11` | (v) x = −24 |
