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प्रश्न
Factorise the following expression.
`1/2y^2-8z^2`
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उत्तर
`1/2y^2 - 8z^2`
= `1/2(y^2 - 16z^2)`
a2 − b2 = (a + b) (a − b)
a = y2
b = 42 = 16
∴ = `1/2[(y)^2 - (4z)^2]`
`1/2(y^2 - 16z^2) = 1/2(y + 4z)(y - 4z)`
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