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Question
Factorise the following expression.
`"p"^2-1/25`
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Solution
`"p"^2 - 1/25`
Let us recognize it as the difference of the squares of a and b.
a = p2
b = `(1/5)^2 = 1/25`
a2 − b2 = (a + b) (a − b)
∴ `(p)^2-(1/5)^2` = `(p + 1/5)(p - 1/5)`
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