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Question
Factorise the following expression.
`"p"^2-1/25`
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Solution
`"p"^2 - 1/25`
Let us recognize it as the difference of the squares of a and b.
a = p2
b = `(1/5)^2 = 1/25`
a2 − b2 = (a + b) (a − b)
∴ `(p)^2-(1/5)^2` = `(p + 1/5)(p - 1/5)`
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The value of p in the equation `(2"p")/3` = 10 is ________
Match the following :
| Column A | Column B |
| (a) `x/2` = 10 | (i) x = 4 |
| (b) 20 = 6x − 4 | (ii) x = 1 |
| (c) 2x − 5 = 3 − x | (iii) x = 20 |
| (d) 7x − 4 − 8x = 20 | (iv) x = `8/3` |
| (e) `4/11 - x = (-7)/11` | (v) x = −24 |
