Advertisements
Advertisements
Question
Factorise the following by taking out the common factor
18xy – 12yz
Advertisements
Solution
18xy – 12yz = (2 × 3 × 3 × y × x) – (2 × 2 × 3 × y × z)
Taking out the common factors 2, 3, y, we get
= 2 × 3 × y(3x – 2z)
= 6y(3x – 2z)
APPEARS IN
RELATED QUESTIONS
Factorise the following expression:
10a2 − 15b2 + 20c2
Factorise the following expression:
x2yz + xy2z + xyz2
Factorize the following:
72x6y7 − 96x7y6
Factories by taking out common factors :
ab(a2 + b2 - c2) - bc(c2 - a2 - b2) + ca(a2 + b2 - c2)
Factories by taking out common factors :
2x(a - b) + 3y(5a - 5b) + 4z(2b - 2a)
Factorise : 12(3x - 2y)2 - 3x + 2y - 1
Factorise : 4(2x - 3y)2 - 8x+12y - 3
Factorise : 2√3x2 + x - 5√3
Factorise : 3x2 + 6x3
Factorise : 4a2 - 8ab
Factorise : 15x4y3 - 20x3y
Factorise : (a+ 2b) (3a + b) - (a+ b) (a+ 2b) +(a+ 2b)2
Factorise xy2 - xz2, Hence, find the value of :
9 x 82 - 9 x 22
Factorise: x4 - 5x2 - 36
Factorise the following by taking out the common factors:
5a(x2 - y2) + 35b(x2 - y2)
Factorise the following by taking out the common factors:
2a(p2 + q2) + 4b(p2 + q2)
Factorise the following by taking out the common factors:
81(p + q)2 -9p - 9q
Factorise the following by taking out the common factors:
(mx + ny)2 + (nx - my)2
Factorise:
4x4 + 25y4 + 19x2y2
