Advertisements
Advertisements
Question
Factorise : 12abc - 6a2b2c2 + 3a3b3c3
Advertisements
Solution
12abc - 6a2b2c2 + 3a3b3c3 = 3abc (4 - 2abc + a2b2c2)
APPEARS IN
RELATED QUESTIONS
Find the common factors of the terms.
2y, 22xy
Find the common factors of the terms.
16x3, −4x2, 32x
Find the common factors of the terms.
10pq, 20qr, 30rp
Factorise the following expression:
20 l2m + 30 alm
Factorise the following expression:
x2yz + xy2z + xyz2
Factorise.
ax + bx − ay − by
Factorize the following:
72x6y7 − 96x7y6
Factorize the following:
2x3y2 − 4x2y3 + 8xy4
Factorise:
5a2 - b2 - 4ab + 7a - 7b
Factorise : 3 - 5x + 5y - 12(x - y)2
Factorise : `1/4 ( a + b )^2 - 9/16 ( 2a - b )^2`
Factorise : 15x4y3 - 20x3y
Factorise: 6xy(a2 + b2) + 8yz(a2 + b2) −10xz(a2 + b2)
Factorise the following by taking out the common factors:
2x5y + 8x3y2 - 12x2y3
Factorise the following by taking out the common factors:
2a(p2 + q2) + 4b(p2 + q2)
Factorise:
`y^2 + (1)/(4y^2) + 1 - 6y - (3)/y`
Factorise:
`"p"^2 + (1)/"p"^2 - 3`
Factorise the following by taking out the common factor
18xy – 12yz
Factorise the following by taking out the common factor
9x5y3 + 6x3y2 – 18x2y
