Advertisements
Advertisements
Question
Factorise : 2b (2a + b) - 3c (2a + b)
Advertisements
Solution
2b (2a + b) - 3c (2a + b) = (2a + b) (2b - 3c)
APPEARS IN
RELATED QUESTIONS
Find the common factors of the terms.
16x3, −4x2, 32x
Factorise the following expression:
7a2 + 14a
Factorise the following expression:
−16z + 20z3
Factorise.
15pq + 15 + 9q + 25p
Factorize the following:
2a4b4 − 3a3b5 + 4a2b5
Factories by taking out common factors :
ab(a2 + b2 - c2) - bc(c2 - a2 - b2) + ca(a2 + b2 - c2)
Factorise:
`x^2 + 1/(4x^2) + 1 - 7x - 7/(2x)`
Factorise : `x^2 + 1/x^2 - 3`
Factorise:
(2a - 3)2 - 2 (2a - 3) (a - 1) + (a - 1)2
Factorise : (a2 - 3a) (a2 - 3a + 7) + 10
Factorise : (a2 - a) (4a2 - 4a - 5) - 6
Find the value of : `[(18.5)^2 - (6.5)^2]/[18.5 + 6.5]`
Factorise : (x + y)(a + b) + (x - y)(a + b)
factorise : 35a3b2c + 42ab2c2
factorise : xy2 + (x - 1) y - 1
factorise : m - 1 - (m-1)2 + am - a
Factorise the following by taking out the common factors:
24m4n6 + 56m6n4 - 72m2n2
Factorise the following by taking out the common factors:
p(p2 + q2 - r2) + q(r2 - q2 -p2) - r(p2 + q2 - r2)
Factorise:
`4"a"^2 + (1)/(4"a"^2) - 2 - 6"a" + (3)/(2"a")`
Factorise the following by taking out the common factor
9x5y3 + 6x3y2 – 18x2y
