Advertisements
Advertisements
प्रश्न
Factorise the following by taking out the common factor
18xy – 12yz
Advertisements
उत्तर
18xy – 12yz = (2 × 3 × 3 × y × x) – (2 × 2 × 3 × y × z)
Taking out the common factors 2, 3, y, we get
= 2 × 3 × y(3x – 2z)
= 6y(3x – 2z)
APPEARS IN
संबंधित प्रश्न
Find the common factors of the terms.
16x3, −4x2, 32x
Factorise the following expression:
5x2y − 15xy2
Factorise the following expression:
ax2y + bxy2 + cxyz
Factorize the following:
72x6y7 − 96x7y6
Factorize the following:
20x3 − 40x2 + 80x
Factorize the following:
28a2 + 14a2b2 − 21a4
Factories by taking out common factors :
xy(3x2 - 2y2) - yz(2y2 - 3x2) + zx(15x2 - 10y2)
Factories by taking out common factors :
2x(a - b) + 3y(5a - 5b) + 4z(2b - 2a)
Factorise : (a2 - 3a) (a2 - 3a + 7) + 10
Factorise : 9x 2 + 3x - 8y - 64y2
Factorise : `1/4 ( a + b )^2 - 9/16 ( 2a - b )^2`
Factorise : a3 - a2 +a
Factorise : 3x2 + 6x3
factorise:
9a (x − 2y)4 − 12a (x − 2y)3
factorise : xy2 + (x - 1) y - 1
Factorise the following by taking out the common factors:
(a - b)2 -2(a - b)
Factorise:
`"p"^2 + (1)/"p"^2 - 3`
Factorise:
5x2 - y2 - 4xy + 3x - 3y
Factorise the following by taking out the common factor
9x5y3 + 6x3y2 – 18x2y
