Advertisements
Advertisements
प्रश्न
factorise : ab(x2 + y2) - xy (a2 + b2)
Advertisements
उत्तर
ab(x2 + y2) - xy (a2 + b2)
= abx2 + aby2 - a2xy - b2xy
= abx2 - a2xy + aby2 - b2xy
= abx2 - a2xy - b2xy + aby2
= ax (bx - ay) - by (bx - ay)
= (bx - ay)(ax - by)
APPEARS IN
संबंधित प्रश्न
Factorise the following expression:
6p − 12q
Factorise the following expression:
10a2 − 15b2 + 20c2
Factorize the following:
5x − 15x2
Factorize the following:
2x3y2 − 4x2y3 + 8xy4
Factorize the following:
9x2y + 3axy
Factorize the following:
x2yz + xy2z + xyz2
Factorise:
`x^2 + 1/(4x^2) + 1 - 7x - 7/(2x)`
Factorise : (a2 - a) (4a2 - 4a - 5) - 6
Factorise : 12(3x - 2y)2 - 3x + 2y - 1
Factorise : 9x 2 + 3x - 8y - 64y2
Find the value of : ( 67.8 )2 - ( 32.2 )2
Factorise : a3 - a2 +a
Factorise : a3b - a2b2 - b3
Factorise : (x + y)(a + b) + (x - y)(a + b)
Factorise : (a+ 2b) (3a + b) - (a+ b) (a+ 2b) +(a+ 2b)2
factorise : a2 - ab - 3a + 3b
Factorise xy2 - xz2, Hence, find the value of :
40 x 5.52 - 40 x 4.52
Factorise:
5x2 - y2 - 4xy + 3x - 3y
