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Factorise the following: 7x^2 + 10xy – 8y^2 - Mathematics

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Question

Factorise the following:

7x2 + 10xy – 8y2

Sum
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Solution

Given: 7x2 + 10xy – 8y2

Step-wise calculation:

1. First, identify two numbers whose product is 7 × (–8) = –56 and whose sum is the middle term coefficient 10.

These numbers are 14 and –4 because 14 × (–4) = –56 and 14 + (–4) = 10.

2. Rewrite the middle term 10xy as 14xy – 4xy:

7x2 + 14xy – 4xy – 8y2

3. Group terms:

(7x2 + 14xy) – (4xy + 8y2)

4. Factor out common terms from each group:

7x(x + 2y) – 4y(x + 2y)

5. Notice the common binomial factor (x + 2y):

(7x – 4y)(x + 2y)

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Chapter 4: Factorisation - Exercise 4D [Page 87]

APPEARS IN

Nootan Mathematics [English] Class 9 ICSE
Chapter 4 Factorisation
Exercise 4D | Q 14. | Page 87
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