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प्रश्न
Factorise the following:
7x2 + 10xy – 8y2
योग
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उत्तर
Given: 7x2 + 10xy – 8y2
Step-wise calculation:
1. First, identify two numbers whose product is 7 × (–8) = –56 and whose sum is the middle term coefficient 10.
These numbers are 14 and –4 because 14 × (–4) = –56 and 14 + (–4) = 10.
2. Rewrite the middle term 10xy as 14xy – 4xy:
7x2 + 14xy – 4xy – 8y2
3. Group terms:
(7x2 + 14xy) – (4xy + 8y2)
4. Factor out common terms from each group:
7x(x + 2y) – 4y(x + 2y)
5. Notice the common binomial factor (x + 2y):
(7x – 4y)(x + 2y)
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