Advertisements
Advertisements
Question
Factorise : a (a - 1) - b (b - 1)
Sum
Advertisements
Solution
a (a - 1) - b (b - 1)
= a2 - a - b2 + b
= a2 - b2 - a + b
= ( a + b )( a - b ) - ( a - b ) [∵ a2 - b2 = ( a + b )( a - b )]
= ( a - b )[( a + b ) - 1]
= ( a - b )[ a + b - 1 ]
shaalaa.com
Method of Factorisation : Difference of Two Squares
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise : 3a5 - 108a3
Factorise : a3 + 2a2 - a - 2
Factorise : 4a2 - 49b2 + 2a - 7b
Factorise : 9a2 + 3a - 8b - 64b2
Factorise : (a + b) 2 - a2 + b2
Factorise : `4x^2 + 1/(4x)^2 + 1`
Factorise the following by the difference of two squares:
16a4 - 81b4
Factorise the following by the difference of two squares:
x2 + y2 - z2 - 2xy
Factorise the following:
`x^2 + (1)/x^2 - 2`
Factorise the following:
4xy - x2 - 4y2 + z2
