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Question
Factorise :
8a3 − b3 − 4ax + 2bx
Sum
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Solution
We know that,
a3 − b3 = ( a − b )( a2 + ab + b2 ) ...(1)
8a3 − b3 − 4ax + 2bx = [(2a)3 − (b)3] − 2x(2a − b)
= (2a − b)[(2a)2 + 2a × b + (b)2 ] − 2x(2a − b) ...[From(1)]
= (2a − b)[4a2 + 2ab + b2] − 2x(2a − b)
= (2a − b)[4a2 + 2ab + b2 − 2x]
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Method of Factorisation : the Sum Or Difference of Two Cubes
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