Question

Factorise : 8a³ - b³ - 4ax + 2bx

Answer 1

We know that,
a³ - b³ = ( a - b )( a² + ab + b² )         .....(1)
8a³ - b³ - 4ax + 2bx
= [ (2a)³ - (b)³ ] - 2 x ( 2a - b )
= ( 2a - b )[ (2a)² + 2a x b + (b)² ] - 2 x ( 2a - b )    [ From(1) ]
= ( 2a - b )[ 4a² + 2ab + b² ] - 2 x ( 2a - b )
= ( 2a - b )[ 4a² + 2ab + b² - 2x ]