Question

Factorisation of – 3a² + 3ab + 3ac is 3a(– a – b – c).

Options

• True

• False

Answer 1

This statement is False.

Explanation:

Let us factorize – 3a² + 3ab + 3ac.

– 3a² + 3ab + 3ac = 3(– a × a + a × b + a × c)

⇒ – 3a² + 3ab + 3ac = 3a(– a + b + c)

But, 3a(– a + b + c) ≠ 3a(– a – b – c)