Advertisements
Advertisements
Question
Factorisation of – 3a2 + 3ab + 3ac is 3a(– a – b – c).
Options
True
False
Advertisements
Solution
This statement is False.
Explanation:
Let us factorize – 3a2 + 3ab + 3ac.
– 3a2 + 3ab + 3ac = 3(– a × a + a × b + a × c)
⇒ – 3a2 + 3ab + 3ac = 3a(– a + b + c)
But, 3a(– a + b + c) ≠ 3a(– a – b – c)
APPEARS IN
RELATED QUESTIONS
Identify the term and its factor in the following expression.
Show the term and factor by tree diagram.
x − 3
Identify the term, their coefficients for the following expression:
3x2y2 − 5x2y2z2 + z2
For the expression, given below, state whether it is a monomial, binomial or trinomial:
2x ÷ 15
Group the like term together: ab, – a2b, – 3ab, 5a2b and – 8a2b
Fill in the blank:
4a + 3b – 7a + 4b = _____
Enclose the given term in bracket as required:
x2 -y2 + z2 + 3x – 2y = x2 – (……..)
Simplify: {9 – (4p – 6q)} – {3q – (5p – 10)}
The value of (a + b)2 + (a – b)2 is ______.
Write the greatest common factor in the following terms.
3x2y, 18xy2, – 6xy
Write the greatest common factor in the following terms.
qrxy, pryz, rxyz
