Advertisements
Advertisements
Question
Factorisation of – 3a2 + 3ab + 3ac is 3a(– a – b – c).
Options
True
False
Advertisements
Solution
This statement is False.
Explanation:
Let us factorize – 3a2 + 3ab + 3ac.
– 3a2 + 3ab + 3ac = 3(– a × a + a × b + a × c)
⇒ – 3a2 + 3ab + 3ac = 3a(– a + b + c)
But, 3a(– a + b + c) ≠ 3a(– a – b – c)
APPEARS IN
RELATED QUESTIONS
Identify the term, their coefficients for the following expression:
9 − ab + bc − ca
In -5x3y2z4 ; write the coefficient of -xy2. Also, write the degree of the given algebraic expression.
Find the numerical co-efficient of the following term:
121bc
Find the numerical co-efficient of the following term:
9pq
Factorise the following expression.
x3y2 + x2y3 – xy4 + xy
Factorise the following expression.
63p2q2r2s – 9pq2r2s2 + 15p2qr2s2 – 60p2q2rs2
Factorise the following expression.
a3 + a2 + a + 1
Identify the term and its factor in the following expression.
Show the term and factor by tree diagram.
5xy2 + 7x2y
Identify term and factor in the expression given below:
− 4x + 5y
3x + 23x2 + 6y2 + 2x + y2 + ______ = 5x + 7y2.
