Advertisements
Advertisements
प्रश्न
Factorisation of – 3a2 + 3ab + 3ac is 3a(– a – b – c).
पर्याय
True
False
Advertisements
उत्तर
This statement is False.
Explanation:
Let us factorize – 3a2 + 3ab + 3ac.
– 3a2 + 3ab + 3ac = 3(– a × a + a × b + a × c)
⇒ – 3a2 + 3ab + 3ac = 3a(– a + b + c)
But, 3a(– a + b + c) ≠ 3a(– a – b – c)
APPEARS IN
संबंधित प्रश्न
Identify term which contain x and give the coefficient of x.
y2x + y
Group the like term together: 9x2, xy, – 3x2, x2 and – 2xy
Group the like term together: ab, – a2b, – 3ab, 5a2b and – 8a2b
In -5x3y2z4 ; write the coefficient of yz2. Also, write the degree of the given algebraic expression.
Find the missing term
_________ × (−15m2n3p) = 45m3n3p2
To add two like terms, its coefficients can be added
Factorised form of r2 – 10r + 21 is ______.
Common factor of 12a2b2 + 4ab2 – 32 is 4.
Write the greatest common factor in the following terms.
qrxy, pryz, rxyz
Identify term which contain x and give the coefficient of x.
5 + z + zx
