Advertisements
Advertisements
प्रश्न
Common factor of 12a2b2 + 4ab2 – 32 is 4.
पर्याय
True
False
Advertisements
उत्तर
This statement is True.
Explanation:
As we have,
12a2b2 + 4ab2 – 32 = 2 × 2 × 3 × a × a × b × b + 2 × 2 × a × b × b – 22 × 23
= 4(3a2b2 + ab2 – 8)
Thus, the common factor is 4.
APPEARS IN
संबंधित प्रश्न
Constant is only 8 other is variable 3x2 × 5x
Group the like term together: 9x2, xy, – 3x2, x2 and – 2xy
Write numerical co-efficient of the following: – 8xy3
Fill in the blank:
6x2y + 13xy2 – 4x2y + 2xy2 = _______
Subtract the second expression from the first:
−2b + 2c, b + 3c
Enclose the given term in bracket as required:
x2 -y2 + z2 + 3x – 2y = x2 – (……..)
Simplify: 8 (2a + 3b – c) – 10 (a + 2b + 3c)
Simplify: `8"x" - ["4y" - {"4x" + ("2x" - bar"2y - 2x")}]`
Common factor of 17abc, 34ab2, 51a2b is ______.
The coefficient of the term – 6x2y2 is – 6.
