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Question
Explain with the help of a balanced equation the brown ring test for nitric acid.
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Solution
Procedure:
- Add freshly prepared saturated solution of iron (II) sulphate to the aq. solution of nitric acid.
- Now add conc. sulphuric acid carefully from the sides of the test tube so that it does not fall dropwise in the test tube.
- Cool the test tube in water.
- A brown ring appears at the junction of the two liquids.
Reaction:
\[\ce{6FeSO4 + 3H2SO4 + 2HNO3 -> 3Fe2(SO4)3 + 4H2O + 2NO}\]
\[\ce{FeSO4 + NO -> \underset{a brown compound]}{\underset{[Nitroso ferrous sulphate,}{FeSO4*NO}}}\]
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