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Question
Explain the following reaction with the balanced equation.
Chlorine dissolved in water
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Solution
Chlorine dissolves in water to form hypochlorous acid and hydrochloric acid.
\[\ce{\underset{\text{Chlorine}}{Cl_{2(g)}} + \underset{\text{Water}}{H2O_{(l)}} -> \underset{\text{Hypochlorous acid}}{HOCl_{(aq)}} + \underset{\text{Hydrochloric acid}}{HCl_{(aq)}}}\]
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