Advertisements
Advertisements
Question
Explain the current flow in an NPN transistor.
Advertisements
Solution
- In NPN transistor electron flow from Emitter to the collector. So conventional current flow from collector to emitter.
- Electrons from the emitter region flow towards the base region constitute emitter current (IE). Electrons after reaching the base region recombine with holes – Most of the electrons reach the collector region. This constitutes collector current (IC). After recombination of holes in the base region by bias voltage VEE constitutes base current IB.
IE = IB + IC [Since base current is very low IC ≈ IC]
APPEARS IN
RELATED QUESTIONS
In a common-base connection, the emitter current is 6.28 mA and the collector current is 6.20 mA. Determine the common-base DC current gain.
Derive the relation between α and β.
With the help of a neat circuit diagram, explain the transistor as an amplifier?
Draw the circuit diagram to study the characteristic of the transistor in common emitter mode. Draw the input and output characteristics.
Explain the need for a feedback circuit in a transistor oscillator.
A transistor having α = 0.8 is connected in common emitter configuration. When the base current changes by 6 mA, then the change in collector current is ______.
Least doped region in a transistor ____________.
In a transistor, doping level in base is increased slightly, the collector current and base current respectively ______.
Explain the working of the n-p-n transistor in a common base configuration.
The collector current in a common-emitter transistor amplifier is 4 mA. When the base current is increased by 20 µA, the collector current increases to 6 mA. The current gain is ______.
